➨ C Programming Floating Point Issues

1. What are the different types of real data type in C ?

A. float, double B. short int, double, long int C. float, double, long double D. double, long int, float - Answer&Explanation Answer:Option C Explanation : The floating point data types are called real data types. Hence float, double, and long double are real data types. View Answer

2. What will you do to treat the constant 3.14 as a long double?

A. use 3.14LD B. use 3.14L C. use 3.14DL D. use 3.14LF - Answer&Explanation Answer:Option B Explanation : Given 3.14 is a double constant. To specify 3.14 as long double, we have to add L to the 3.14. (i.e 3.14L) View Answer

3. If the binary eauivalent of 5.375 in normalised form is 0100 0000 1010 1100 0000 0000 0000 0000, what will be the output of the program (on intel machine)? #include<stdio.h> #include<math.h> int main() { float a=5.375; char *p; int i; p = (char*)&a; for(i=0; i<=3; i++) printf("%02x\n", (unsigned char)p[i]); return 0; }

A. 40 AC 00 00 B. 04 CA 00 00 C. 00 00 AC 40 D. 00 00 CA 04 - Answer&Explanation Answer:Option C Explanation : No answer description available for this question. View Answer

4. Which of the following range is a valid long double (Turbo C in 16 bit DOS OS) ?

A. 3.4E-4932 to 1.1E+4932 B. 3.4E-4932 to 3.4E+4932 C. 1.1E-4932 to 1.1E+4932 D. None of these - Answer&Explanation Answer:Option A Explanation : The range of long double is 3.4E-4932 to 1.1E+4932 View Answer

5. Which statement will you add in the following program to work it correctly? #include<stdio.h> int main() { printf("%f\n", log(36.0)); return 0; }

A. #include<conio.h> B. #include<math.h> C. #include<stdlib.h> D. #include<dos.h> - Answer&Explanation Answer:Option B Explanation : math.h is a header file in the standard library of C programming language designed for basic mathematical operations. Declaration syntax: double log(double); View Answer

6. We want to round off x, a float, to an int value, The correct way to do is

A. y = (int)(x + 0.5) B. y = int(x + 0.5) C. y = (int)x + 0.5 D. y = (int)((int)x + 0.5) - Answer&Explanation Answer:Option A Explanation : Rounding off a value means replacing it by a nearest value that is approximately equal or smaller or greater to the given number. y = (int)(x + 0.5); here x is any float value. To roundoff, we have to typecast the value of x by using (int) Example: #include <stdio.h> int main () { float x = 3.6; int y = (int)(x + 0.5); printf ("Result = %d\n", y ); return 0; } Output: Result = 4. View Answer

7. The binary equivalent of 5.375 is

A. 101.101110111 B. 101.011 C. 101011 D. None of above - Answer&Explanation Answer:Option B Explanation : No answer description available for this question. View Answer

8. A float occupies 4 bytes. If the hexadecimal equivalent of these 4 bytes are A, B, C and D, then when this float is stored in memory in which of the following order do these bytes gets stored?

A. ABCD B. DCBA C. 0xABCD D. Depends on big endian or little endian architecture - Answer&Explanation Answer:Option D Explanation : No answer description available for this question View Answer

9. What will you do to treat the constant 3.14 as a float?

A. use float(3.14f) B. use 3.14f C. use f(3.14) D. use (f)(3.14) - Answer&Explanation Answer:Option B Explanation : Given 3.14 is a double constant. To specify 3.14 as float, we have to add f to the 3.14. (i.e 3.14f) View Answer

10. Which of the following statement obtains the remainder on dividing 5.5 by 1.3 ?

A. rem = (5.5 % 1.3) B. rem = modf(5.5, 1.3) C. rem = fmod(5.5, 1.3) D. Error: we can't divide - Answer&Explanation Answer:Option C Explanation : fmod(x,y) - Calculates x modulo y, the remainder of x/y. This function is the same as the modulus operator. But fmod() performs floating point divisions. Example : #include <stdio.h> #include <math.h> int main () { printf ("fmod of 5.5 by 1.3 is %lf\n", fmod (5.5, 1.3) ); return 0; } Output: fmod of 5.5 by 1.3 is 0.300000 View Answer